Yan & Hanson
[8]
and Makate & Sattayatham
[6]
extended Bates’ model to the stochastic volatility model with jumps in both the stock price and the variance processes. As the solution processes of finding the characteristic function, they sought such a function f satisfying
f(ℓ,ν,t; k,T) = exp(g(τ) + vh(τ) + ixl).
We add the term of order
ν
1/2
to the exponent in the above equation and seek the explicit solution of
f
.
1. INTRODUCTION
The Heston model
[5]
is the following risk-neutral stock price processes
where
St
is a stock process,
r
is the riskless rate of return,
vt
is the volatility of asset returns,
κ
> 0 is a mean-reverting rate,
θ
is the long term variance,
σ
> 0 is the volatility of volatility, and
and
are two correlated Brownian motions under the risk-neutral measure with constant correlation coefficient
ρ
The Bates
[1]
extended the Heston model (1.1) to include jumps in the stock price process. The model has the following dynamics which define the evolution of
St
satisfying
where the volatility process
νt
is the same as one in the Heston model and the driving Brownian motions in the two processes have an instantaneous correlation coefficient
ρ
, the process
represents a Poisson process under the risk-neutral measure, with jump intensity λ. The Poisson process is independent of the two Brownian motions in the stock price and the variance processes. The percentage jump size of the stock price is denoted by the random variable
Yt
with log-normal distribution.
Eraker et al.
[3]
extended Bates model to a stochastic volatility model with contemporaneous jumps in the stock price and its volatility
Eraker et al. tested their model with empirical data and showed that the models with jumps performed better than those without jumps in volatility. Makate and Sattayatham
[6]
provide a formal ’closed-form solution’ of the stochastic-volatility jump-diffiusion model.
Heston’s
[5]
’closed-form solution’ for risk-neutral pricing of European options is given by first converting the problem into characteristic functions, then using the Fourier inversion formula for probability distribution functions to find a more numerically robust form which everyone won’t call it closed. To solve for the characteristic function
fj
explicitly, Yan & Hanson
[8]
and Makate & Sattayatham
[6]
conjecture that its solution is given by
where
β
1
(
τ
) = 0 and
β
2
(
τ
) =
rτ
. In this paper, we add the term of order
ν
1/2
to the exponent in (1.3) for the exploit of nonlinearity and seek the explicit solution of
fj
.
This paper is structured as follows. The introduction is given in Section 1. The stochastic-volatility jump-diffiusion model is explained in detail in Section 2. The formulation for European call option pricing is given in Section 3.
2. STOCHASTIC-VOLATILITY JUMP-DIFFUSION MODEL
We assume that a risk-neutral probability measure
Q
exists. We also assume that the asset price
St
under
Q
follows a jump- diffiusion process, and the volatility
νt
follows a pure mean-reverting and square root diffiusion process with jump,
e.g
., our model is governed by the following dynamics
where
St
,
νt
,
κ
,
θ
,
σ
,
,
are the same ones defined as in Bates model (1.2),
r
is a risk-free interest rate,
and
are independent Poisson processes with constant intensities
λS
and
λν
respectively.
Yt
is the jump size of the asset price return with density
ϕY
(
y
) and
E
[
Yt
] =
m
, and
Zt
is the jump size of the volatility with density
ϕZ
(
z
). Moreover, we assume that the Poisson processes
and
are independent of standard Brownian motions
and
with
3. FORMULATION FOR EUROPEAN CALL OPTION PRICING
Let
C
denote the price at time
t
of a European style call option on
St
with strike price
K
and expiration time
T
. The terminal payoff of a European call option on the underlying stock
St
is
Assume that the short-term risk-free interest rate
r
is constant over the lifetime of the option. The price of the European call at time
t
equals the discounted and conditional expected payoff
where
EQ
is the expectation with respect to the risk-neutral probability measure
Q
and
PQ
(
ST
|
St
,
νt
) is the corresponding conditional density function given (
St
,
νt
).
Since
is a risk-neutral probability such that
-
ST>K, EQ[ST|St,νt] =er(T−t)St.
P
2
(
St
,
νt
,
T
;
K
,
T
) =
ProbQ
(
ST
>
K
|
St
,
νt
) is the risk-neutral in-the-money probability. Note that the complement of
P
2
is a risk-neutral distribution function. It is difficult to find the cumulative distribution function in European option pricing. The main job is to evaluate
P
1
and
P
2
under the distribution assumptions embedded in the risk-neutral probability measure.
We make a change of variable from
St
to
Lt
= ln
St
. Let
k
= ln
K
. By the jump-diffiusion chain rule, ln
St
satisfies the SDE
The value
C
of a European-style option as a function of
Lt
becomes
that is, we have
The Dynkin’s theorem
[4]
shows a relationship between stochastic diffierential equations and partial diffierential equations. If we apply two-dimensional Dynkin’s theorem for the price dynamics (3.2) and volatility
νt
in (2.1b) to
(
Lt
,
νt
,
t
;
k
,
T
), then we obtain the following Partial Integro-Diffierential Equations (PIDE)
where
is defined as
In the current state variables
Lt = ℓ
and
νt = ν
, the option value (3.1) becomes
where
for
j
= 1, 2.
Lemma 3.1
(
[6]
).
The functions
in (3.3) satisfies the following PIDEs
with the boundary condition at expiration time t = T
in (3.3) also satisfies the following PIDEs
with the boundary condition at expiration time t = T
A
1
and
A
2
in Lemma 3.1 are respectively defined as
and
For
j
= 1, 2 the characteristic functions for
with respect to the variable
k
are defined as
in which a minus sign is given to account for the negativity of the measure
For
j
= 1, 2,
fj
satisfies similar PIDEs as in (3.4) and (3.5)
with the boundary conditions
since
Let’s find the characteristic functions
fj
for
j
= 1, 2. Let
τ = T − t
be the time to go. We seek the functions
f
1
and
f
2
satisfying
-
f1(ℓ,ν,t;k,T) = exp(g1(τ) +ν1/2h1(τ) + (ν1/2)2h2(τ) +ixℓ),
-
f2(ℓ,ν,t;k,T) = exp(g2(τ) +ν1/2h3(τ) + (ν1/2)2h4(τ) +ixℓ+rτ).
respectively with the boundary conditions
-
gi(0) = 0 =hj(0) fori= 1, 2 andj= 1, 2, 3, 4.
Lemma 3.2.
The functions
and
can be computed by the inverse Fourier transforms of the characteristic function, e.g.
,
for j
= 1, 2.
Re
[·]
denote the real part of the complex number.
The characteristic function f
1
is given by
-
f1(ℓ,ν,t;k,T) = exp(g1(τ) +ν1/2h1(τ) +νh2(τ) +ixℓ.
h
2
is given by
where η
1
=
ρσ
(
ix
+ 1) −
κ and
h
1
is given by
where γ
1
(0+)
represents a small value factor which appears in the coefficient of ν
1/2
as the one of ν
3/2
.
which is equal to the equations as in
[6]
if the coefficient h
1
(
τ
)
of order ν
1/2
is zero
.
The characteristic function f
2
is given by
-
f2(ℓ,ν,T;k,T) = exp(g2(τ) +ν1/2h3(τ) +νh4(τ) +ixℓ+rτ).
h
4
is given by
where η
2
=
ρσix − κ and
h
3
is given by
where γ
2
(0+)
represents a small value factor which appears in the coefficient of ν
1/2
as the one of ν
3/2
.
which is equal to the equations as in
[6]
if the coefficient h
3
(
τ
)
of order ν
1/2
is zero
.
Theorem 3.3.
The value of a European call option of (3.3) is
where
and
are given in Lemma 3.2.
Now we prove Lemma 3.2.
Proof
. For the derivation of the equation (3.7), refer to the paper
[6]
. Let us compute PDE (3.6). First let’s calculate some diffierentials regarding to
f
1
.
-
f1(ℓ+y,ν,t;x,t+τ) −f1(ℓ,ν,t;x,t+τ) = (eixy− 1)f1(ℓ,ν,t;x,t+τ).
We use the series expansion, which is valid only when |
z
| <
ν
in the following equation.
If we substitute the above diffierentials and equations into the equation (3.6), then we have
The coefficients of
ν
are
The solution of
h
2
(
τ
) is given by
where η
1
=
ρσ
(
ix
+ 1) −
κ and
(See
[6]
for detail). The coefficients of
ν
1/2
are
where we denote
γ
1
(0+) a small value factor which appears in the coefficient of
ν
1/2
as the one of
ν
3/2
. We seek
h
1
(
τ
) as series solution such as
h
2
can be written as
where
A
1
=
σ
−2
(
η
1
+ Δ
1
),
B
1
= (
η
1
+ Δ
1
) / (
η
1
− Δ
1
). Substituting (3.9) and (3.10) into (3.8), we obtain
which can be solved in turn.
The constant terms are
By integrating (3.11) from 0 to
τ
, we obtain
Similarly, we can compute
h
3
,
h
4
and
g
2
. □
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1996
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,
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7